Отображение веб-сервера получения данных JSON в ListView

Вы можете попробовать что-то похожее на следующее:

public String getDataString() {
String someString = "";

JSONObject jsonObj = getData();
Log.i("JSON string =>", jsonObj.toString());

String text= null;

try {
// Handle cols
JSONArray cols = jsonObj.getJSONArray("cols");
int i = 0;
Log.i("i", i+ "," + cols.length() ); //TODO delete this
while(i<cols.length()) {

JSONObject obj= cols.getJSONObject(i);
String labelType = obj.getString("label");

if(labelType.equals("time"))
{
text = obj.getString("datetime");
}
else if(labelType.equals("Temperature"))
{
text = obj.getString("number");
}

// Do something with String text

i++;
}
// Handle rows
JSONArray rows= jsonObj.getJSONArray("rows");
int i = 0;
Log.i("i", i+ "," + rows.length() ); //TODO delete this
while(i<rows.length()) {

JSONObject obj= rows.getJSONObject(i);
JSONArray cObj= obj.getJSONArray("c");
JSONObject vFirst = cObj.getJSONObject(0);
JSONObject vSecond = cObj.getJSONObject(1);

String firstString = vFirst.getString("v");
String secondString = vSecond .getString("v");

// Do something with String firstString and/or String secondString

i++;
}

}

} catch (JSONException e) {
Log.e("testing","Failed to load JSON");
e.printStackTrace();
}
.
.
.
// Return some string
return someString;
.
.
.
}public static JSONObject getData() {

HttpGet httpGet = new HttpGet("YOUR_URI_HERE");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();

try {
response = client.execute(httpGet);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}

JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
} catch (JSONException e) {
e.printStackTrace();
}

return jsonObject;
}