Как я могу отправить себе по электронной почте запрос RAW SQL, который производит эта функция php?

Я хочу запустить объяснение для медленного запроса, но я не знаю, как просмотреть сырой sql, поэтому я могу запустить его в phpmyadmin и отладить его. Вот функция.

    private function getAttImages($limit, $forumIds = 0, $fidsReverse = false, $topicIds = 0, $membersIds = 0, $order = 'attach_date', $sort = 'desc', $group = null)
{
$fids = '';

if ($forumIds)
{
$r = '';
if ($fidsReverse)
{
$r = ' NOT ';
}

if (is_array($forumIds))
{
$forumIds = implode(',', $forumIds);
}

$fids = ' AND forums_topics.forum_id ' . $r . ' IN (' . $forumIds .  ')';
}

$tids = '';
if ($topicIds)
{
$tids = ' AND forums_topics.tid IN (' . $topicIds . ')';
}

$mids = '';
if ($membersIds)
{
$mids = ' AND core_attachments.attach_member_id IN (' . $membersIds . ')';
}$whereT = array();
$joinsT = array();

$findInPosts = ' AND ' . \IPS\Db::i()->findInSet('queued', array('0'));
$joinsT[] = array(
'select'    => 'forums_posts.*',
'from'      => 'forums_posts',
'where'     => array("forums_posts.pid=core_attachments_map.id2" . $findInPosts),
);

$findInTopics = ' AND ' . \IPS\Db::i()->findInSet('approved', array('1'));
$joinsT[] = array(
'select'    => 'forums_topics.*',
'from'      => 'forums_topics',
'where'     => array("forums_topics.tid=forums_posts.topic_id" . $findInTopics . $fids . $tids),
);

$select = 'core_attachments.attach_id AS custom_data, core_attachments.*';
if ($group)
{
$select = 'core_attachments.attach_id AS custom_data, COUNT(attach_is_image) as cnt_images, SUM(attach_hits) as summ_attach_hits, core_attachments.*';
}

$joinsT[] = array(
'select'    => $select,
'from'      => 'core_attachments',
'where'     => array('core_attachments.attach_is_image=1 AND core_attachments.attach_is_archived=0 AND core_attachments.attach_id=core_attachments_map.attachment_id' . $mids),

);

$joinsT[] = array(  'select'    => 'core_members.member_id, core_members.member_group_id, core_members.mgroup_others, core_members.name, core_members.members_seo_name',
'from'      => 'core_members',
'where'     => array('core_attachments.attach_member_id=core_members.member_id' . $mids),
);

$joinsT[] = array(  'select'    => 'core_permission_index.perm_id',
'from'      => 'core_permission_index',
'where'     => array("core_permission_index.app='forums' AND core_permission_index.perm_type='forum' AND core_permission_index.perm_type_id=forums_topics.forum_id"),
);

$groupT = $group;

$whereT[] = array(
"core_attachments_map.location_key='forums_Forums' AND " .
\IPS\Db::i()->findInSet('perm_view', array_merge(array(\IPS\Member::loggedIn()->member_group_id), array_filter(explode(',', \IPS\Member::loggedIn()->mgroup_others)))) . " OR perm_view='*'" .
$fids . $tids . $mids
);

$table = new \IPS\Helpers\Table\Db(
'core_attachments_map',
\IPS\Http\Url::internal('app=core&module=system&controller=nbattachpictures', 'front', 'nbattachpictures'),
$whereT,
$groupT
);

$table->joins = $joinsT;
$table->sortBy = $order;
$table->sortDirection = $sort;
$table->limit = $limit;

$table->rowsTemplate = array(\IPS\Theme::i()->getTemplate('plugins', 'core', 'global'), 'nbAttachmentsBlocksRows');

$table->parsers = array(
'custom_data' => function( $val, $row )
{
return array(
'topic_data' => \IPS\Http\Url::internal("app=forums&module=forums&controller=topic&id={$row['tid']}", 'front', 'forums_topic', array($row['title_seo'])),
'summ_attach_hits' => $row['summ_attach_hits'],
'jewel' => $this->attachJewel($row['summ_attach_hits']),
);
},
);

return $table;
}

Кто-нибудь знает, как я могу видеть SQL-запрос только то, что производится этой функцией? электронная почта лучше, чем эхо, так как я хочу получить запрос с живого сайта.