Итерация по объекту JSON с детьми

Question

Итерация по объекту JSON с детьми

Я использую fancytree для отправки данных через ajax.

$("#save").click(function(e){
e.preventDefault();

var tree = $("#tree").fancytree("getTree").rootNode;
var data = tree.toDict(true);
data = JSON.stringify(data);
$.ajax(
{
type: "POST",
data :  { "data": data },
contentType: "application/json",
success: function(data) {
$('#alert').empty().append(data);
}
});
});

Данные JSON являются следующим форматом. Мне нужно повторить следующий порядок объектов JSON для манипулирования данными.

{
"expanded":true,
"key":"root_1",
"selected":false,
"title":"root",
"children":
[
{"key":"p_1","selected":false,"title":"Animal Meat"},
{"key":"p_2","selected":false,"title":"Animal Product"},
{"folder":true,"key":"p_3","selected":false,"title":"Beverage","children":
[
{"key":"2","selected":false,"title":"Tea"},
{"key":"3","selected":false,"title":"Coffee"},
{"key":"4","selected":false,"title":"Water"}
]},
{"folder":true,"key":"p_4","selected":true,"title":"Cereal","children":
[
{"key":"6","selected":true,"title":"Porridge"}
]},
{"folder":true,"key":"p_5","selected":false,"title":"Dairy Product","children":
[
{"key":"7","selected":false,"title":"Cheese"},
{"key":"8","selected":false,"title":"Curd"},
{"key":"10","selected":false,"title":"Milk"},
]}
]}

Следующая функция в Laravel обрабатывает этот запрос.

public function storePreference(Request $request)
{
$data = $request->getContent();

$data = urldecode($data);

foreach($data['children'] as $child)
{
$key      = $child['key'];
$selected = $child['selected'];
$title    = $child['title'];

printf("Key: %s, selected: %s, title: %s\n", $key, $selected ? "true" : "false", $title);
}
}

Мне нужен следующий вывод:

Key: p_1, selected: false, title: Animal Meat
Key: p_2, selected: false, title: Animal Product
Key: p_3, selected: false, title: Beverage
Key: 2, selected: false, title: Tea
Key: 3, selected: false, title: Coffee
Key: 4, selected: false, title: Water
Key: p_4, selected: true, title: Cereal
Key: 6, selected: true, title: Porridge
Key: p_5, selected: false, title: Dairy Product
and so on...

Я использую fancytree для отправки этих данных в Laravel 5.

Любая помощь приветствуется.

-1

fancytree json laravel-5 php

Решение

Другие решения

Мне нужно было удалить «data =» из строки $ data и использовать json_decode.

public function storePreference(Request $request)
{
$data = $request->getContent('data');

$data = urldecode($data);
$data = substr($data, 5);
$data = json_decode($data, true);
foreach($data['children'] as $child)
{
$key      = $child['key'];
$selected = $child['selected'];
$title    = $child['title'];

printf("<p>Key: %s, selected: %s, title: %s\n", $key, $selected ? "true" : "false", $title);

if (isset($child['children']))
{
foreach ($child['children'] as $c)
{
$key      = $c['key'];
$selected = $c['selected'];
$title    = $c['title'];
printf("<p>Key: %s, selected: %s, title: %s\n", $key, $selected ? "true" : "false", $title);

}
}

}
}

Спасибо @jeromegamez за помощь.

0

Источник

Accepted Answer

$json = <<<JSON
{
"expanded":true,
"key":"root_1",
"selected":false,
"title":"root",
"children":
[
{"key":"p_1","selected":false,"title":"Animal Meat"},
{"key":"p_2","selected":false,"title":"Animal Product"},
{"folder":true,"key":"p_3","selected":false,"title":"Beverage","children":
[
{"key":"2","selected":false,"title":"Tea"},
{"key":"3","selected":false,"title":"Coffee"},
{"key":"4","selected":false,"title":"Water"}
]},
{"folder":true,"key":"p_4","selected":true,"title":"Cereal","children":
[
{"key":"6","selected":true,"title":"Porridge"}
]},
{"folder":true,"key":"p_5","selected":false,"title":"Dairy Product","children":
[
{"key":"7","selected":false,"title":"Cheese"},
{"key":"8","selected":false,"title":"Curd"},
{"key":"10","selected":false,"title":"Milk"}
]}
]}
JSON;

$data = json_decode($json, true);

foreach ($data['children'] as $child) {
$key      = $child['key'];
$selected = $child['selected'];
$title    = $child['title'];

printf("Key: %s, selected: %s, title: %s\n", $key, $selected ? "true" : "false", $title);
}

Это выведет:

Key: p_1, selected: false, title: Animal Meat
Key: p_2, selected: false, title: Animal Product
Key: p_3, selected: false, title: Beverage
Key: p_4, selected: true, title: Cereal
Key: p_5, selected: false, title: Dairy Product

Обновить: Я изменил JSON в моем примере, потому что JSON из исходного поста был недействительным на момент написания этой статьи (например: вторая до последней строки в оригинальном JSON содержала завершающую запятую).

Метод Ларавела:

public function storePreference(Request $request)
{
$dataString = $request->getContent();
$dataString = urldecode($data);
$dataString = json_decode($dataString, 'data=');

$data = json_decode($dataString, true);

foreach($data['children'] as $child)
{
$key      = $child['key'];
$selected = $child['selected'];
$title    = $child['title'];

printf("Key: %s, selected: %s, title: %s\n", $key, $selected ? "true" : "false", $title);
}
}

1