Android-клиент получает изображение с PHP-сервера

Я пытаюсь отправить изображение через скрипт PHP, поэтому ImageView изменения на клиенте Android.

На данный момент я получаю это и так без изменения изображения.

D/skia: --- SkAndroidCodec::NewFromStream returned null

Любая помощь будет с благодарностью исправить это. Ура 🙂

Вот мой код Android:

public class MainActivity extends AppCompatActivity {

ImageView imageView;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

imageView = (ImageView) findViewById(R.id.imageView);

}

private class getImage extends AsyncTask<String, String, String> {

HttpURLConnection conn;
URL url = null;

public getImage(){
}

@Override
protected String doInBackground(String... params) {
Log.d("TAG", "CALLED");

try {
// Enter URL address where your php file resides
url = new URL(<absolute_path_to_file>);

} catch (MalformedURLException e) {
e.printStackTrace();
return e.toString();
}
try {
// Setup HttpURLConnection class to send and receive data from php and mysql
conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("POST");

// setDoInput and setDoOutput to true as we send and recieve data
conn.setDoInput(true);
conn.setDoOutput(true);

// add parameter to our above url
String weekDay;
SimpleDateFormat dayFormat = new SimpleDateFormat("EEEE", Locale.ENGLISH);

Calendar calendar = Calendar.getInstance();
weekDay = dayFormat.format(calendar.getTime());

Uri.Builder builder = new Uri.Builder().appendQueryParameter("item_index", "FOUR");
String query = builder.build().getEncodedQuery();

OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
writer.write(query);
writer.flush();
writer.close();
os.close();
conn.connect();

} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
return e1.toString();
}

try {

int response_code = conn.getResponseCode();

// Check if successful connection made
if (response_code == HttpURLConnection.HTTP_OK) {

// Read data sent from server
InputStream input = conn.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(input));
StringBuilder result = new StringBuilder();
String line;

while ((line = reader.readLine()) != null) {
result.append(line);
}

// Pass data to onPostExecute method
return (result.toString());

} else {
return("Connection error");
}

} catch (IOException e) {
e.printStackTrace();
return e.toString();
} finally {
conn.disconnect();
}
}

@Override
protected void onPostExecute(String result) {

InputStream is;

try{
is = conn.getInputStream();
//get image from server
Bitmap bitmap = BitmapFactory.decodeStream(is);
imageView.setImageBitmap(bitmap);
is.close();
} catch (IOException e){
Log.d("TAG", "ERROR: " + e);
}

}
}

}

Вот мой скрипт PHP-сервера:

<?php

if(isset($_POST['item_index'])){

$filename = "leo.jpg";
$location = "leo.jpg";
$mimeType="application/octet-stream";

if(!file_exists($location))
{ header ("HTTP/1.0 404 Not Found");
return;
}

$size=filesize($location);
$time=date('r',filemtime($location));
#html response header
header('Content-Description: File Transfer');
header("Content-Type: $mimeType");
header('Cache-Control: public, must-revalidate, max-age=0');
header('Pragma: no-cache');
header('Accept-Ranges: bytes');
header('Content-Length:'.($size));
header("Content-Disposition: inline; filename=$filename");
header("Content-Transfer-Encoding: binary\n");
header("Last-Modified: $time");
header('Connection: close');

ob_clean();
flush();
readfile($location);

}


?>