Допустим, у меня есть следующий пример программы на C ++:
#include <iostream>
using namespace std;
int main (int argc , char** argv) {
int a = 1;
int b = 2;
int& aRef = a;
int& bRef = b;
aRef = bRef; // This just sets aRef to point to b?
aRef = 3; // Now aRef points to a new int 3 not stored in a other variable?
// a = 3 b = 2
bRef = 4;
// a = 3 b = 4
aRef = long(&bRef); // Why do we need long casting here?
bRef = 5;
// a: varying b = 5 // Why is a varying?
aRef = bRef;
bRef = 6;
// a = 5 b = 6 // Why a no more varying?
}
Может ли кто-нибудь объяснить это построчно и, возможно, выявить ошибки? Я добавил комментарии к строкам, которые мне не совсем понятны.
#include <iostream>
using namespace std;
int main (int argc , char** argv) {
int a = 1;
int b = 2;
int& aRef = a; // aRef is now another name for a
int& bRef = b; // bRef is now another name for b
aRef = bRef; // same as a = b
aRef = 3; // same as a = 3
bRef = 4; // same as b = 4
aRef = long(&bRef); // &bRef is the same as &b - i.e. take address of b - stores address in a
bRef = 5; // same as b = 5
aRef = bRef; // same as a = b
bRef = 6; // same as b = 6
}
Других решений пока нет …