Ошибка компиляции при использовании boost :: future .then ()

Я пытаюсь использовать функциональность boost :: future .then ().
Фрагмент взят из Документация по синхронизации потоков Boost 1.54.0

#include <string>
#include <boost/thread/future.hpp>
int main() {
boost::future<int> f1 = boost::async([]() { return 123; });
boost::future<std::string> f2 = f1.then([](boost::future<int> f)->std::string {
int x = f.get();
return ("Done" + std::to_string(x));
});
}

Настроить :
Ubuntu 13.04
g ++ версия g ++ (Ubuntu 4.8.1-2ubuntu1 ~ 13.04) 4.8.1
Boost версия 1.54.0

командная строка :

g++  then_test.cc -std=c++0x -DBOOST_THREAD_VERSION=4 -I        /home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost -L /home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/stage/lib -static -lboost_thread-mt -lboost_date_time-mt  -lboost_system-mt -lpthread

Ошибка:

g++  then_test.cc -std=c++0x -DBOOST_THREAD_VERSION=4 -I /home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost -L /home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/stage/lib -static -lboost_thread-mt -lboost_date_time-mt  -lboost_system-mt -lpthread
then_test.cc: In function ‘int main()’:
then_test.cc:10:44: error: no matching function for call to ‘boost::future<int>::then(main()::__lambda1)’
});
^
then_test.cc:10:44: note: candidates are:
In file included from then_test.cc:2:0:
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp:1598:9: note: template<class F> boost::future<typename boost::result_of<F(boost::future<R>&)>::type> boost::future<R>::then(F&&) [with F = F; R = int]
then(BOOST_THREAD_FWD_REF(F) func);
^
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp:1598:9: note:   template argument deduction/substitution failed:
In file included from then_test.cc:2:0:
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp: In substitution of ‘template<class F> boost::future<typename boost::result_of<F(boost::future<R>&)>::type> boost::future<R>::then(F&&) [with F = F; R = int] [with F = main()::__lambda1]’:
then_test.cc:10:44:   required from here
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp:62:29: error: no type named ‘type’ in ‘struct boost::result_of<main()::__lambda1(boost::future<int>&)>’
#define BOOST_THREAD_FUTURE future
^
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp:3840:3: note: in expansion of macro ‘BOOST_THREAD_FUTURE’
BOOST_THREAD_FUTURE<R>::then(BOOST_THREAD_FWD_REF(F) func)
^
In file included from then_test.cc:2:0:
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp:1601:9: note: template<class F> boost::future<typename boost::result_of<F(boost::future<R>&)>::type> boost::future<R>::then(boost::launch, F&&) [with F = F; R = int]
then(launch policy, BOOST_THREAD_FWD_REF(F) func);
^
/home/prakash/maidsafe/MaidSafe/build/boost_1_54_0/src/boost/boost/thread/future.hpp:1601:9: note:   template argument deduction/substitution failed:
then_test.cc:10:44: note:   cannot convert ‘<lambda closure object>main()::__lambda1{}’ (type ‘main()::__lambda1’) to type ‘boost::launch’
});

Пожалуйста, дайте мне знать, если я что-то здесь упускаю.