Неправильный DCT с функцией MKL DCT

Я даю 8×8 входных данных для моего кода дискретного косинусного преобразования (DCT) на основе MKL:

«fileinput.txt» ВХОД:

255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255
255    255    255    255    255    255    255    255

DCT ВЫХОД ИЗ НИЖЕГО КОДА как:

32385      -727.349243  -619.955444 -458.675903 -267.323547 -74.151535  92.318069   207.505844
764.404419  717.50531   602.316772  435.846893  242.6754    51.322887   -109.956779 -217.350159
-762.619629 -706.582764 -583.869446 -412.598663 -218.058334 -28.972321  126.74057   226.088898
759.648132  694.603516  564.651367  388.979492  193.525208  7.147152    -142.635284 -233.70639
-755.498901 -681.59967  -544.712891 -365.049927 -169.138    14.096443   157.598663  240.180206
750.180115  667.597656  524.094971  340.860809  144.948898  -34.714363  -171.600922 -245.499771
-743.705566 -652.633789 -502.85144  -316.473694 -121.019257 54.652824   184.604614  249.648224
736.088623  636.739502  481.026154  291.940552  97.400169   -73.870857  -196.583725 -252.620102

ОЖИДАЕМЫЙ ВЫХОД:

16320      8.331551    -8.493903    8.775995    -9.19324    9.772106    -10.552611  11.595706
8.332954    0.004307    -0.004317   0.004504    -0.00472    0.004989    -0.005391   0.00592
-8.494178   -0.004317   0.004454    -0.004576   0.004765    -0.005109   0.005472    -0.006031
8.776941    0.004504    -0.004545   0.004746    -0.004965   0.005248    -0.005666   0.006251
-9.193484   -0.004659   0.004811    -0.00495    0.005198    -0.005507   0.005955    -0.006519
9.771847    0.005035    -0.005079   0.005241    -0.005522   0.005852    -0.006314   0.00696
-10.552428  -0.005383   0.005533    -0.005627   0.00591    -0.006314    0.006844    -0.007483
11.59587    0.005882    -0.00605    0.006274    -0.006557   0.006974    -0.007506   0.008264

КОД:

#include <time.h>
#include <stdlib.h>
#include "mkl.h"#include "iostream"using namespace std;

int main(int argc, char* argv[]){
float *dpar;
float *out;
MKL_INT *ipar;
MKL_INT tt_type,stat,n_1,nn;
FILE *fp;

fp = fopen( "D:\\fileinput.txt","r" );if(fp == NULL){
cout<<"file not created properly"<<endl;
}
printf("\n===== DCT CODE ======== \n");
DFTI_DESCRIPTOR_HANDLE handle = 0;
int n = 64;//8x8 matrix;
nn = (MKL_INT)n;
tt_type = MKL_COSINE_TRANSFORM;

n_1 = nn + 1 ;
out = (float*)malloc((n+1)*sizeof(float));
dpar= (float*)malloc((5*n_1/2+2)*sizeof(float));
ipar= (MKL_INT*)malloc((128)*sizeof(int));
s_init_trig_transform(&n_1,&tt_type,ipar,dpar,&stat);
for (int srcSize =0 ;srcSize< n ; srcSize++)
{
fscanf(fp,"%f\n",&out[srcSize]);
}
fclose(fp);
if (stat != 0)
{
printf("\n============================================================================\n");
printf("FFTW2MKL FATAL ERROR: MKL TT initialization has failed with status=%d\n",(MKL_INT)stat);
printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
printf("to find what went wrong...\n");
printf("============================================================================\n");
return NULL;
}
ipar[10] = 1;    //nx, that is, the number of intervals along the x-axis, in the Cartesian case.
ipar[11] = 1;    //ny, that is, the number of intervals along the x-axis, in the Cartesian case.
ipar[14] = n_1;  //specifies the internal partitioning of the dpar array.
ipar[15] = 1;    //value of ipar[14]+1,Specifies the internal partitioning of the dpar array.
s_commit_trig_transform(out,&handle,ipar,dpar,&stat);
if (stat != 0)
{
printf("\n============================================================================\n");
printf("FFTW2MKL FATAL ERROR: MKL TT commit step has failed with status=%d\n",(MKL_INT)stat);
printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
printf("to find what went wrong...\n");
printf("============================================================================\n");
return NULL;
}
s_forward_trig_transform(out,&handle,ipar,dpar,&stat);
if (stat != 0)
{
printf("\n============================================================================\n");
printf("FFTW2MKL FATAL ERROR: MKL TT commit step has failed with status=%d\n",(MKL_INT)stat);
printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
printf("to find what went wrong...\n");
printf("============================================================================\n");
return NULL;
}

free_trig_transform(&handle,ipar,&stat);
printf("\n===== DCT GOT OVER ======== \n");return 0;

}

Можете ли вы направить меня, чтобы выяснить, какую ошибку я совершаю в своем коде

0

Решение

Больше вопроса, чем ответа. Эти 4 строки правильны?

ipar[10] = 1;    //nx, that is, the number of intervals along the x-axis,
ipar[11] = 1;    //ny, that is, the number of intervals along the x-axis,
ipar[14] = n_1;  //specifies the internal partitioning of the dpar array.
ipar[15] = 1;    //value of ipar[14]+1,Specifies the ... of the dpar array.

В первых двух случаях число интервалов действительно равно 1?

В четвертом случае комментарий гласит, что ipar[15] это значение ipar[14]+1 = n_1 + 1 = nn + 2 = n + 2 = 66хотя мы не знаем, что происходит с n_1 в s_init_trig_transform(),

0

Другие решения


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